l***g
发帖数: 1035 | 1 // is the following code compilable? is the cast operating on the value (tem
p) or the address?
int temp = 2;
...
foo((double)&temp); | k**f
发帖数: 372 | 2
tem
My understanding is that you are trying to cast an address to an integer to
a double, which is hardly correct.
If foo() expects an address to a double as its input, you need to declare an
intermediate variable, say x, of type double, initialized to the value of
temp, and then call foo() with the address of x: foo(&x). If foo modifies
its input, you can then assign x to temp (may loss fractional part, though).
【在 l***g 的大作中提到】
: // is the following code compilable? is the cast operating on the value (tem
: p) or the address?
: int temp = 2;
: ...
: foo((double)&temp);
| n****g
发帖数: 150 | 3 works well on C/C++ compilers, nothing wrong with it. | h******e
发帖数: 26 | 4 语句的意思是把temp变量的“地址”转换为double类型
“地址”这东西通常是32/64位的整数，把这个转换为double类型……语法上没问题，
语义上就难说了…… |
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