c*******9
发帖数: 6411 | 1 assuming we have the code:
try{
function();
}
catch(exception e)
{
log(..)
}
int i = 1;
...
when some code inside function() throw an exception and get caught here,
after log(..)
will the program continue to execute the statement "int i=1", or it just
stop?
thanks... | X****r
发帖数: 3557 | 2 Yes, unless log(..) throws.
【在 c*******9 的大作中提到】
: assuming we have the code:
: try{
: function();
: }
: catch(exception e)
: {
: log(..)
: }
: int i = 1;
: ...
|
|
