k*****6
发帖数: 26 | 1 有python比较熟练的朋友帮忙看下这两道题吗？万分感激。。
Do both of these problems using at least one loop each and not using any
special pre-existing functions that give you the answer with just one line
of code.
1. Make a function to count the number of times a specified number is
repeated in a list/array. That means that if we have a number list
numberList=[5, 12, 0, 7, 2, 5, 10, 9, 12, 5];
and we use the function call
numRepeats(numberList, 5)
we get the output: 3 --- meaning 5 occurs three times in numberList.
2. Make a function that takes in a multi-dimensional array/list and returns
the "diagonal" --- a list of the elements at the 1st row-and-1st column, 2nd
row-and-2nd column, 3rd row-and-3rd column, etc. That means if we have a
multi-dimensional array:
multiArray = [[3, -4, 12, 5], [5, 2, 11, -5], [2, 2, 0, 5], [-5, -3, 2, 2]
];
and we use the function call
diagonal(multiArray)
we get the output [3, 2, 0, 2] . | i***r
发帖数: 1035 | 2 第一个可以用dictionary，最后用value sort。
第二个用enumerate就可以做，或者map function | a****f
发帖数: 17 | 3 1 sum([1 for ele in numberList if ele == 5])
2 [ele[i] for i,ele in enumerate(inArray)]
【在 k*****6 的大作中提到】
: 有python比较熟练的朋友帮忙看下这两道题吗？万分感激。。
: Do both of these problems using at least one loop each and not using any
: special pre-existing functions that give you the answer with just one line
: of code.
: 1. Make a function to count the number of times a specified number is
: repeated in a list/array. That means that if we have a number list
: numberList=[5, 12, 0, 7, 2, 5, 10, 9, 12, 5];
: and we use the function call
: numRepeats(numberList, 5)
: we get the output: 3 --- meaning 5 occurs three times in numberList.
| a****e
发帖数: 9589 | 4 1, y = collections.Counter(x)
2,y = numpy.diag(x)
楼上的都没问题，取决于职位。如果应聘初级职位，一楼的方法足矣；中级level 的，
用二楼的；老人级别的，就得用叔的啦。
【在 k*****6 的大作中提到】
: 有python比较熟练的朋友帮忙看下这两道题吗？万分感激。。
: Do both of these problems using at least one loop each and not using any
: special pre-existing functions that give you the answer with just one line
: of code.
: 1. Make a function to count the number of times a specified number is
: repeated in a list/array. That means that if we have a number list
: numberList=[5, 12, 0, 7, 2, 5, 10, 9, 12, 5];
: and we use the function call
: numRepeats(numberList, 5)
: we get the output: 3 --- meaning 5 occurs three times in numberList.
| i****k
发帖数: 668 | 5 显然你挂了。。。因为英语没学好和人沟通存在问题。。。
【在 a****e 的大作中提到】
: 1, y = collections.Counter(x)
: 2,y = numpy.diag(x)
: 楼上的都没问题，取决于职位。如果应聘初级职位，一楼的方法足矣；中级level 的，
: 用二楼的；老人级别的，就得用叔的啦。
| a****e
发帖数: 9589 | 6 还是你懂叔。
人之所以是人，就是因为会使用前人用过的工具和总结出的知识。
这个出题的人连这都不懂，偏要自己写。幼齿啊。
【在 i****k 的大作中提到】
: 显然你挂了。。。因为英语没学好和人沟通存在问题。。。
| j**********3
发帖数: 3211 | 7 人家不是特意说不能one line 么？楼上怎么都是一行的 |
|
