d**e
发帖数: 6098 | 1 好像很繁琐，只处理 n>= 0。谁能提供一个简易版？怎么处理负数的情况？
char * intToBinStr(int n)
{
char * binStr = 0;
int length = 0;
int remainder = 0;
int factor = 1;
int result = 0;
if(n == 0)
{
binStr = new char('0');
}
else{
while (n >= 1)
{
remainder = n % 2;
result += remainder * factor;
n = n / 2;
factor *= 10;
length++;
}
binStr = new char[length];
while(result >= 1)
{
binStr[--length] = '0' + (result % 10);
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