c******k
发帖数: 1140 | 1 请帮忙做个题：看似简单，但不知怎么做
InP Fabry-Perot 激光器的 L-I curves （见图）, 有三个不同的阈值电流，对应三个
不同的cavity lengths：150um, 300um, and 600um.
其他条件： 激光器发射1.55um的光, confinement factor:0.3,
an effective index of InP: n=3.2, a device width of 2um,
an active region thickness of 200nm,
a bimolecular recombination coefficient of B=10^-10 cm^3/s.
请帮忙估计一下internal waveguide loss。或者给点指点，怎么算， 多谢了！！！ | R****a
发帖数: 199 | 2 First question for you, do you know the output power is one-facet or two-
facet?
Second, it would be very helpful if you could plot the L-I curve into (
photon number)-(electron number).
The refractive index n is used to calculate the reflectivity of the two
facets. (One simple question for you, do you know what that is?)
Another question, can we assume the confinement factor for current is 1? I
do not know much about bimolecular recombination, could you explain it a
little bit?
【在 c******k 的大作中提到】
: 请帮忙做个题：看似简单，但不知怎么做
: InP Fabry-Perot 激光器的 L-I curves （见图）, 有三个不同的阈值电流，对应三个
: 不同的cavity lengths：150um, 300um, and 600um.
: 其他条件： 激光器发射1.55um的光, confinement factor:0.3,
: an effective index of InP: n=3.2, a device width of 2um,
: an active region thickness of 200nm,
: a bimolecular recombination coefficient of B=10^-10 cm^3/s.
: 请帮忙估计一下internal waveguide loss。或者给点指点，怎么算， 多谢了！！！
| c******k
发帖数: 1140 | 3 Thank for your feedback.
1. The output power is for two-facet.
2. This is a 作业题。原题的描述就是这个样子。
3. I know R=((n-1)/(n+1))^2
4. We can assume the confinement factor for current is 1, and I don't know
the bimolecular recombination too.
By the way, I know g=alpha+ln(1/R)/L
But I have no idea how to get a relation between g (gain coefficient) and
threshold current.
【在 R****a 的大作中提到】
: First question for you, do you know the output power is one-facet or two-
: facet?
: Second, it would be very helpful if you could plot the L-I curve into (
: photon number)-(electron number).
: The refractive index n is used to calculate the reflectivity of the two
: facets. (One simple question for you, do you know what that is?)
: Another question, can we assume the confinement factor for current is 1? I
: do not know much about bimolecular recombination, could you explain it a
: little bit?
| R****a
发帖数: 199 | 4
What I mean is you need draw a picture like that output photo number per
second vs input electron per second. By that way, you can solve the problem
more easily.
Then you have a known number in the following equestion.
what you wrote is gth (the threshold gain per unit length) . This is the
threshold. For different length of the cavity, the gth is different due to
the fact that L is different.
g is proportional to current (actually, should be proportional to the
current density, current per uni
【在 c******k 的大作中提到】
: Thank for your feedback.
: 1. The output power is for two-facet.
: 2. This is a 作业题。原题的描述就是这个样子。
: 3. I know R=((n-1)/(n+1))^2
: 4. We can assume the confinement factor for current is 1, and I don't know
: the bimolecular recombination too.
: By the way, I know g=alpha+ln(1/R)/L
: But I have no idea how to get a relation between g (gain coefficient) and
: threshold current.
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