z****e
发帖数: 2024 | 1 class Base{
public:
virtual void Method();
};
void Base::Method(){cout<<"Base::method"<
class D2:public Base{
private:
void Method(){cout<<"D2::method"<
};
void peek(Base& b){
b.Method();
}
int main(){
D2 d;
peek(d);
}
>D2::method
为什么D2虚函数是私有，但是通过一个global函数，仍然有多态？
虚函数的访问权限改变，有作用吗？
早谢。 |
N***m
发帖数: 4460 | 2 guess it is still in v-table so you can still use pointer to access it
【在 z****e 的大作中提到】
: class Base{
: public:
: virtual void Method();
: };
: void Base::Method(){cout<<"Base::method"<: class D2:public Base{
: private:
: void Method(){cout<<"D2::method"<: };
: void peek(Base& b){
|
t****t
发帖数: 6806 | 3 In short, access checking is static, although virtual function binding is
dynamic.
11.6 Access to virtual functions [class.access.virt]
1 The access rules (clause _class.access_) for a virtual function are
determined by its declaration and are not affected by the rules for a
function that later overrides it. [Example:
class B {
public:
virtual int f();
};
class D : public B {
private:
int f();
};
void f()
{
D d;
B* pb = &d;
【在 z****e 的大作中提到】
: class Base{
: public:
: virtual void Method();
: };
: void Base::Method(){cout<<"Base::method"<: class D2:public Base{
: private:
: void Method(){cout<<"D2::method"<: };
: void peek(Base& b){
|
z****e
发帖数: 2024 | 4 orz。
【在 t****t 的大作中提到】
: In short, access checking is static, although virtual function binding is
: dynamic.
: 11.6 Access to virtual functions [class.access.virt]
: 1 The access rules (clause _class.access_) for a virtual function are
: determined by its declaration and are not affected by the rules for a
: function that later overrides it. [Example:
: class B {
: public:
: virtual int f();
: };
|
