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发帖数: 418 | 1 【 以下文字转载自 Programming 讨论区 】
发信人: treeq (treeq), 信区: Programming
标 题: 如何用python web.py web service 做 multiple parameters 的 call?
发信站: BBS 未名空间站 (Sun Mar 22 23:14:33 2015, 美东)
大家好。我的那个web service 做成了。用了python 的 web.py.
install web.py
cd webpy
编辑python web service.
#!/usr/bin/env python
import web
import csv
import difflib
import re
import operator
import Levenshtein
urls = ('/title_matching2','title_matching2')
app = web.application(urls,globals())
class title_matching2:
def __init__(self):
self.hello = "hello world"
def GET(self):
getInput = web.input(name="World")
b=[]
with open("Book1.txt","rb") as k:
for row in k:
b.append(row.split("t"))
k.close()
c=[]
with open("series_name.txt","rb") as j:
for row in j:
c.append(row.split("t"))
j.close()
d=[]
with open("season_name.txt","rb") as s:
for row in s:
d.append(row.split("t"))
s.close()
dd={}
ee={}
cc={}
gg={}
title=str(getInput.name)
title1=re.sub(r',',' ',title)
title1=title1.lower()
title1=re.sub(r'series',' ',title1)
title1=re.sub(r'episode',' ',title1)
title1=re.sub(r'season',' ',title1)
title1=re.sub(r'"',' ',title1)
title1=re.sub(r'-',' ',title1)
title1=re.sub(r':',' ',title1)
title1=re.sub(r' ','',title1)
for j in range(len(b)):
s2=re.sub(r',',' ',b[j][3])
s2=s2.lower()
s2=re.sub(r'series',' ',s2)
s2=re.sub(r'episode',' ',s2)
s2=re.sub(r'season',' ',s2)
s2=re.sub(r'"',' ',s2)
s2=re.sub(r'-',' ',s2)
s2=re.sub(r':',' ',s2)
s2=re.sub(r' ','',s2)
b[j].append(s2)
s3=re.sub(r',',' ',b[j][3]).lower()
b[j].append(s3)
for t in range(len(c)):
s2=re.sub(r',',' ',c[t][0])
s2=s2.lower()
s2=re.sub(r'series',' ',s2)
s2=re.sub(r'episode',' ',s2)
s2=re.sub(r'season',' ',s2)
s2=re.sub(r'"',' ',s2)
s2=re.sub(r'-',' ',s2)
s2=re.sub(r':',' ',s2)
s2=re.sub(r' ','',s2)
c[t].append(s2)
for q in range(len(d)):
s2=re.sub(r',',' ',d[q][0])
s2=s2.lower()
s2=re.sub(r'series',' ',s2)
s2=re.sub(r'episode',' ',s2)
s2=re.sub(r'season',' ',s2)
s2=re.sub(r'"',' ',s2)
s2=re.sub(r'-',' ',s2)
s2=re.sub(r':',' ',s2)
s2=re.sub(r' ','',s2)
d[q].append(s2)
ff={}
for j in range(len(b)):
d1=float(Levenshtein.ratio(title1,b[j][len(b[j])-2]))
ff[str(b[j][2])+"t"+str(b[j][3]).strip()+"t"+b[j][len(b[j])-1].
strip()]=d1
qq=title1
dd[qq]=str(max(ff.iteritems(),key=operator.itemgetter(1))[0])
my_list=qq+"t"+dd[qq]
# max_value=float(max(max_value,d))
return gg
if __name__ == "__main__":
app.run()
kk=my_list.split("t")
matchObj=re.match(r'(.+)-(.+)-(.+)',kk[3].strip())
if matchObj:
ee={}
cc={}
for e in range(len(c)):
d2=float(Levenshtein.ratio(str(matchObj.group(1)),c[e][len(c[e]
)-1]))
ee[str(c[e][0]+"t"+c[e][1].strip())]=d2
for r in range(len(d)):
d3=float(Levenshtein.ratio(str(matchObj.group(1)+matchObj.group
(2)),d[r][len(d[r])-1]))
cc[str(d[r][0]+"t"+d[r][1].strip())]=d3
uu=str(max(ff.iteritems(),key=operator.itemgetter(1))[0]).split("t
")
gg['matched title']=uu[1]
gg['matched title WPR_ID']=uu[0]
gg['matched title confidence level']=max(ff.iteritems(),key=
operator.itemgetter(1))[1]
return gg
if __name__ == "__main__":
app.run()
然后 run 这个 web service , ./some.py, 再call:
links http://localhost:8080/title_matching2?title=diehard
会返回一个hash table. 正是我想要的。
但是如果run multiple parameters 的话：
代码如下：
#!/usr/bin/env python
import web
import csv
import difflib
import re
import operator
import Levenshtein
urls = ('/title_matching4','title_matching4')
app = web.application(urls,globals())
class title_matching4:
def __init__(self):
self.hello = "hello world"
def GET(self):
getInput = web.input(title="World",prod="type")
b=[]
with open("Book3.txt","rb") as k:
for row in k:
b.append(row.split("t"))
k.close()
dd={}
ee={}
cc={}
qq={}
title1=str(getInput.title)
prod1=str(getInput.prod)
title1=re.sub(r',',' ',title1)
title1=title1.lower()
title1=re.sub(r'series',' ',title1)
title1=re.sub(r'episode',' ',title1)
title1=re.sub(r'season',' ',title1)
title1=re.sub(r'"',' ',title1)
title1=re.sub(r'-',' ',title1)
title1=re.sub(r':',' ',title1)
title1=re.sub(r' ','',title1)
prod1=prod1.lower()
s4=title1+prod1
for j in range(len(b)):
s2=re.sub(r',',' ',str(b[j][1]))
s2=s2.lower()
s2=re.sub(r'series',' ',s2)
s2=re.sub(r'episode',' ',s2)
s2=re.sub(r'season',' ',s2)
s2=re.sub(r'"',' ',s2)
s2=re.sub(r'-',' ',s2)
s2=re.sub(r':',' ',s2)
s2=re.sub(r' ','',s2)
s3=str(b[j][3].strip())
s3=s3.lower()
s5=s2+s3
b[j].append(s5)
ff={}
for j in range(len(b)):
d1=float(Levenshtein.ratio(s4,b[j][len(b[j])-1]))
ff[str(b[j][1]).strip()+"t"+str(b[j][2]).strip()+"t"+str(b[j][3
]).strip()]=d1
qqq=title1
dd[qqq]=str(max(ff.iteritems(),key=operator.itemgetter(1))[0])+"t"+
str(max(ff.iteritems(),key=operator.itemgetter(1))[1])
my_list=dd[qqq]+"t"+qqq
# max_value=float(max(max_value,d))
my_list1=my_list.split("t")
qq['matched title']=my_list1[0]
qq['matched WPR_id']=my_list1[1]
qq['matched title confidence level']=my_list1[3]
return qq
if __name__ == "__main__":
app.run()
然后再run ./rest9.py
再打开一个link:
links http://localhost:8080/title_matching4?title=diehard&prod=feature
就没有hash table 返回。虽然我想返回hash table.
只是出现如下东西在screen 上：
ubuntu@ip-10-0-0-126:~$ links http://localhost:8080/title_matching4?title=diehard&prod=feature
[1] 1190
请问这是为什么？
为什么不能打开一个连接，并有hash table 返回？
多谢！
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