o*******e
发帖数: 31 | 1 I want to use awk to realize following goal:
when the line matches some Regular Expression, parsing
the line and output.
if the line doesn't match, don't make parsing and output
the original line.
I try to use if block like this:
if ( $0 ~ /expression/ )
{ printf "total energy =" ,$NF}
else
{printf $0}
But it doesn't work.
/expression/ {print "total energy =", $NF}
can find the desired line and output as I wish, but
I lose the control of other lines.
I don't know what's wrong with my cod | h******a
发帖数: 198 | 2 /expression/{print "total energy=",$NF};!/expression/{print}
【在 o*******e 的大作中提到】
: I want to use awk to realize following goal:
: when the line matches some Regular Expression, parsing
: the line and output.
: if the line doesn't match, don't make parsing and output
: the original line.
: I try to use if block like this:
: if ( $0 ~ /expression/ )
: { printf "total energy =" ,$NF}
: else
: {printf $0}
| o*******e
发帖数: 31 | 3 Thx!
BTW, what does the semicolon mean?
How to use "if" to solve the problem?
【在 h******a 的大作中提到】
: /expression/{print "total energy=",$NF};!/expression/{print}
| o*******e
发帖数: 31 | 4
How does awk deal with a series of pattern {action} ?
excute all actions for one line first
or excute one action for all lines first?
【在 o*******e 的大作中提到】
: Thx!
: BTW, what does the semicolon mean?
: How to use "if" to solve the problem?
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