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CS版 - [转载] Help for the min value. Thanks
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相关话题的讨论汇总
话题: value话题: min话题: sum话题: i0话题: i1
进入CS版参与讨论
1 (共1页)
b******n
发帖数: 147
1
【 以下文字转载自 Mathematics 讨论区,原文如下 】
发信人: beautumn (星星草), 信区: Mathematics
标 题: Help for the min value. Thanks
发信站: Unknown Space - 未名空间 (Mon Oct 25 12:53:28 2004) WWW-POST
Please help me.....
SUM of a_i is N; where i is changed from 1 to m
SUM of b_i is N; where i is changed from 1 to m
So, what is the max/min value of (SUM of a_i*b_i),where i is changed from 1 to
m.
The max value is N^2 where a_i0=b_i0=N and a_i1=b_i1=0 for all i1<>i0, right?
How do I know the min value? I think it should be like
b******n
发帖数: 147
2
Sorry, I forgot to mention it. If the case (a_1=N, b_1=0; a_2=0, b_2=N) is
impossible to appear in the real experiment,what is the min (non-zero) value?

to
right?

【在 b******n 的大作中提到】
: 【 以下文字转载自 Mathematics 讨论区,原文如下 】
: 发信人: beautumn (星星草), 信区: Mathematics
: 标 题: Help for the min value. Thanks
: 发信站: Unknown Space - 未名空间 (Mon Oct 25 12:53:28 2004) WWW-POST
: Please help me.....
: SUM of a_i is N; where i is changed from 1 to m
: SUM of b_i is N; where i is changed from 1 to m
: So, what is the max/min value of (SUM of a_i*b_i),where i is changed from 1 to
: m.
: The max value is N^2 where a_i0=b_i0=N and a_i1=b_i1=0 for all i1<>i0, right?

1 (共1页)
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相关话题的讨论汇总
话题: value话题: min话题: sum话题: i0话题: i1