n**d
发帖数: 9764 | 1 Why the output is the same after I change longjmp(kansas, 47) to longjmp(
kansas, 0)? The code should not go to "else" becasue the return value is 0
for longjmp(kansas, 0).
#include
#include
using namespace std;
class Rainbow {
public:
Rainbow() { cout << "Rainbow()" << endl; }
~Rainbow() { cout << "~Rainbow()" << endl; }
};
jmp_buf kansas;
void oz() {
Rainbow rb;
for(int i = 0; i < 3; i++)
cout << "there's no place like home" << endl;
longjmp(kansas, 47);
}
int main | t****t
发帖数: 6806 | 2 不看手册？
DESCRIPTION
longjmp() and setjmp(3) are useful for dealing
with errors and interrupts encountered in a
low-level subroutine of a program. longjmp()
restores the environment saved by the last call
of setjmp(3) with the corresponding env argu-
ment. After longjmp() is completed, program
execution continues as if the corresponding
call of setjmp(3) had just returned the value
val. longjmp() cannot cause 0 to
【在 n**d 的大作中提到】
: Why the output is the same after I change longjmp(kansas, 47) to longjmp(
: kansas, 0)? The code should not go to "else" becasue the return value is 0
: for longjmp(kansas, 0).
: #include
: #include
: using namespace std;
: class Rainbow {
: public:
: Rainbow() { cout << "Rainbow()" << endl; }
: ~Rainbow() { cout << "~Rainbow()" << endl; }
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