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Statistics版 - transform to gaussian?
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相关话题的讨论汇总
话题: gaussian话题: transform话题: malvague话题: cdf话题: non
进入Statistics版参与讨论
1 (共1页)
k******w
发帖数: 269
1
who know this transform of non gaussian to gaussian?
maybe the name is sth like Malvague S. transform
thanks
d*****y
发帖数: 140
2
i am not so sure, but intuitively, i would like to do the following things:
Let a be the r.v. you want to transform from with cdf F(x), and G(x) be the
cdf of gaussian distribution, G^{-1}(x) is its invers function, then
G^{-1}(F(a)) is a gaussian r.v.
当然,应该会有更好的办法,呵呵

【在 k******w 的大作中提到】
: who know this transform of non gaussian to gaussian?
: maybe the name is sth like Malvague S. transform
: thanks

l********s
发帖数: 430
3
box-cox
k******w
发帖数: 269
4
yes, it is this method
but, I just know the R.V. is non gaussian, how to do regression with it?
just give assumption on F(x)?thanks again

the

【在 d*****y 的大作中提到】
: i am not so sure, but intuitively, i would like to do the following things:
: Let a be the r.v. you want to transform from with cdf F(x), and G(x) be the
: cdf of gaussian distribution, G^{-1}(x) is its invers function, then
: G^{-1}(F(a)) is a gaussian r.v.
: 当然,应该会有更好的办法,呵呵

d*****y
发帖数: 140
5
如果你不知道F(x)的具体形式,那么假设你有N个a的sample, R(a_i)是a_i的rank,
then
G^{-1}[R(a_i)/N] 可以认为是gaussian
regression这个问题就深了,我也不太清楚了,浪费您感情了-,-

【在 k******w 的大作中提到】
: yes, it is this method
: but, I just know the R.V. is non gaussian, how to do regression with it?
: just give assumption on F(x)?thanks again
:
: the

1 (共1页)
进入Statistics版参与讨论
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相关话题的讨论汇总
话题: gaussian话题: transform话题: malvague话题: cdf话题: non