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Computation版 - 怎样实现正态分布函数从某个数x到正无穷大的积分?
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1 (共1页)
c******a
发帖数: 45
1
Thanks a lot!
c*******e
发帖数: 8624
2
什么叫怎么实现?

【在 c******a 的大作中提到】
: Thanks a lot!
r****y
发帖数: 1437
3

Just numerically integrate it from x to a very large number, say 10000.
Depending on your requirement of precision, sometimes just to 100 would be
enough.
Or another approach, do integration from 0 to x, and you know the integral
from 0 to inf is sqrt(pi)/2. So you know the integral from x to inf.
Exp(-x^2) is dropping very fast from 0 to inf, accumulated contribution
outside 10 FWHM is really small.

【在 c******a 的大作中提到】
: Thanks a lot!
w*********r
发帖数: 488
4
you can transform the variable x to its associated probaliliy given that you
know this varible has what kind of distribution. for example:
phi(x)=z, z belongs to [0,1], the unbounded integral is transformed into the
bounded integral ,but you also need to changed the pdf , new pdf is equal to
the "old" pdf times the Jacobian of the transformation.

【在 c******a 的大作中提到】
: Thanks a lot!
b***n
发帖数: 53
5
转换成标准正态分布然后查表
http://www.math.unb.ca/~knight/utility/NormTble.htm

【在 c******a 的大作中提到】
: Thanks a lot!
1 (共1页)
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