R******y
发帖数: 651 | 1 忘了具体说的是啥。大致是说一个complex variable z, 一个analytic function f(z)
如果 |z*f(z)| goes to zero as z goes to infinite, then infinite contour
integral f(z)dz is zero. 谁给回忆一下这个定理的名字是？印象里是叫做Jordan
theorem？ | d*********0
发帖数: 222 | 2 没听过啊。
证明是不是因为无穷是可取奇点，所以积分为0？
z)
【在 R******y 的大作中提到】
: 忘了具体说的是啥。大致是说一个complex variable z, 一个analytic function f(z)
: 如果 |z*f(z)| goes to zero as z goes to infinite, then infinite contour
: integral f(z)dz is zero. 谁给回忆一下这个定理的名字是？印象里是叫做Jordan
: theorem？
| x******n
发帖数: 24 | 3 $\infty$ is a removable singularity of z*f(z) and you can give value 0 i
n Riemaanian sphere C\cup {\infty}, which give you $\infty$ is a removab
le singulary of f(z), then your result comes from Cauchy's integral theo
rem.
z)
【在 R******y 的大作中提到】
: 忘了具体说的是啥。大致是说一个complex variable z, 一个analytic function f(z)
: 如果 |z*f(z)| goes to zero as z goes to infinite, then infinite contour
: integral f(z)dz is zero. 谁给回忆一下这个定理的名字是？印象里是叫做Jordan
: theorem？
| R******y
发帖数: 651 | 4 Thanks, I got your point.
【在 x******n 的大作中提到】
: $\infty$ is a removable singularity of z*f(z) and you can give value 0 i
: n Riemaanian sphere C\cup {\infty}, which give you $\infty$ is a removab
: le singulary of f(z), then your result comes from Cauchy's integral theo
: rem.
:
: z)
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